The lonely runner problem
“Conjectures” on the running track?


The conjecture then states that, for any collection v1,v2,…,vn−1 of positive, distinct speeds, there exists some time t > 0 such that
1/n ≤ frac(vit) ≤ 1 − 1/n.
Consider the time τi = 1/vi it takes each runner to complete one circuit of the unit track. If the times τi are all rational (or at least if they are all commensurate with one another) then they have a least common multiple, and the ratio of that least common multiple to the greatest common divisor of the track times has a prime factorization. A solution to the Chinese Remainder Theorem will then put all the runners but one in their places to leave that runner “lonely” at some time t > 0, and at every multiple of the least common multiple of track times after that.
If not all of the times τi are commensurate with one another, then the runners can be partitioned into classes, such that all the runners of each class are running at speeds that are commensurable, that is, in rational ratios to each other in the same class, but no two runners of different classes are running at commensurable speeds.
The Chinese Remainder Theorem may then be solved for each commensurable class of runners, and these solutions may be combined by applying Dirichlet’s Diophantine Approximation Theorem to prove the existence of a time when each runner is “lonely” in the general case.

It appears unfortunately as though we are being “played” by the gentlemen of the district with their various propositions and conjectures at the running track. Maybe we are missing something here, or, it is a trick question.



